AMC 8 1986 Problem 3

AMC8 1986 年第 3 题

表达式与运算★☆☆☆☆
The smallest sum one could get by adding three different numbers from the set {7,25,−1,12,−3}\{ 7,25,-1,12,-3 \} is
从集合 {7,25,−1,12,−3}\{7,25,-1,12,-3\} 中选三个不同的数相加,能得到的最小和是
  1. A.-3
  2. B.-1
  3. C.3
  4. D.5
  5. E.21

正确答案 · Correct Answer

C

解析 · Solution

Solution 1

The smallest possible sum is found by adding the 3 smallest elements of the set. This sum is (-3)+ (-1) + 7 = 3.

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