AMC 8 1987 Problem 11

AMC8 1987 年第 11 题

表达式与运算★★★☆☆
The sum 217+312+5119\displaystyle 2\frac17+3\frac12+5\frac{1}{19} is between
和 217+312+5119\displaystyle 2\frac17+3\frac12+5\frac{1}{19} 在以下哪两个数之间?
  1. A.10 and 101210\text{ and }10\frac12
  2. B.1012 and 1110\frac12 \text{ and } 11
  3. C.11 and 111211\text{ and }11\frac12
  4. D.1112 and 1211\frac12 \text{ and }12
  5. E.12 and 121212\text{ and }12\frac12

正确答案 · Correct Answer

B

解析 · Solution

Solution 1

Since 17<14\displaystyle \frac{1}{7} < \frac14 and 119<14\displaystyle \frac{1}{19} < \frac14, it follows that 217+312+5119<214+312+514=11\displaystyle 2\frac17+3\frac12+5\frac{1}{19} < 2\frac14+3\frac12+5\frac14 = 11. Also, 217+312+5119>2+312+5=1012\displaystyle 2\frac17+3\frac12+5\frac{1}{19} > 2+3\frac12+5 = 10\frac12. Therefore, the sum is between 1012 and 11\displaystyle 10\frac{1}{2} \text{ and } 11.

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