AMC 8 1987 Problem 6

AMC8 1987 年第 6 题

表达式与运算★★☆☆☆
The smallest product one could obtain by multiplying two numbers in the set {−7,−5,−1,1,3}\{ -7,-5,-1,1,3 \} is
将集合 {−7,−5,−1,1,3}\{-7,-5,-1,1,3\} 中的两个数相乘,能得到的最小乘积是
  1. A.-35
  2. B.-21
  3. C.-15
  4. D.-1
  5. E.3

正确答案 · Correct Answer

B

解析 · Solution

Solution 1

Choosing the positive and negative numbers with the highest absolute values minimizes this product, which in this case is −7⋅3=−21-7 \cdot 3 = -21.

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