AMC 8 1987 Problem 9

AMC8 1987 年第 9 题

整除与因数★★☆☆☆
When finding the sum 12+13+14+15+16+17\displaystyle \frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{6}+\frac{1}{7} , the least common denominator used is
求 12+13+14+15+16+17\displaystyle \frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{6}+\frac{1}{7} 的和时,使用的最小公分母是
  1. A.120
  2. B.210
  3. C.420
  4. D.840
  5. E.5040

正确答案 · Correct Answer

C

解析 · Solution

Solution 1

The least common denominator is lcm(2,3,4,5,6,7)=lcm(2,3,22,5,2⋅3,7)=22⋅3⋅5⋅7=420\mathrm{lcm}(2, 3, 4, 5, 6, 7) = \mathrm{lcm}(2, 3, 2^2, 5, 2\cdot 3, 7) = 2^2 \cdot 3 \cdot 5 \cdot 7 = 420.

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