AMC 8 1989 Problem 1

AMC8 1989 年第 1 题

数列与规律★☆☆☆☆

题干整理中

  1. A.150
  2. B.199
  3. C.200
  4. D.249
  5. E.250

正确答案 · Correct Answer

E

解析 · Solution

Solution 1

Rearranging terms yields (1+49)+(11+39)+(21+29)+(31+19)+(41+9)=50+50+50+50+50=50⋅5=250(1+49)+(11+39)+(21+29)+(31+19)+(41+9) = 50+50+50+50+50 =50\cdot 5 = 250.

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