AMC 8 1989 Problem 13

AMC8 1989 年第 13

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Problem 9/7×53 =
9/7×53 =
  1. A..9.7×53\displaystyle \frac{.9}{.7×53}
  2. B..9.7×.53\displaystyle \frac{.9}{.7\times.53}
  3. C..9.7×5.3\displaystyle \frac{.9}{.7×5.3}
  4. D..97×.53\displaystyle \frac{.9}{7\times.53}
  5. E..09.07×.53\displaystyle \frac{.09}{.07\times.53}

正确答案 · Correct Answer

A

解析 · Solution

解析整理中

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