AMC 8 1989 Problem 17

AMC8 1989 年第 17 题

方程与不等式★★★☆☆
The number NN is between 9 and 17 . The average of 6 , 10 , and NN could be
数 NN 在 9 到 17 之间。6、10 和 NN 的平均数可能是
  1. A.8
  2. B.10
  3. C.12
  4. D.14
  5. E.16

正确答案 · Correct Answer

B

解析 · Solution

Solution 1

The smallest possible average is 6+10+93=253=813\displaystyle \frac{6 + 10 + 9}{3} = \frac{25}{3} = 8\frac{1}{3}, while the highest possible average is 6+10+173=333=11\displaystyle \frac{6+10+17}{3} = \frac{33}{3} = 11. The only answer choice between 813\displaystyle 8\frac{1}{3} and 11 is 10, which would be the average if N = 14.

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