AMC 8 1990 Problem 15

AMC8 1990 年第 15 题

四边形与多边形★★★☆☆
The area of this figure is 100 cm2100\text{ cm}^2 . Its perimeter is [figure consists of four identical squares]
此图形的面积为 100 cm2100\text{ cm}^2。其周长是
[图形由四个相同的正方形组成]
  1. A.20 cm\text{20 cm}
  2. B.25 cm\text{25 cm}
  3. C.30 cm\text{30 cm}
  4. D.40 cm\text{40 cm}
  5. E.50 cm\text{50 cm}

正确答案 · Correct Answer

E

解析 · Solution

Solution 1

Since the area of the whole figure is 100 cm2100\text{ cm}^2, each square has an area of 1004=25 cm2\displaystyle \frac{100}{4} = 25\text{ cm}^2 and a side length of 25=5 cm\sqrt{25} = 5\text{ cm}.
The boundary of this figure is made of 10 segments, each of length 5 cm5\text{ cm}, so it perimeter is 10⋅5=50 cm10 \cdot 5=50\text{ cm}.

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