AMC 8 1991 Problem 21

AMC8 1991 年第 21 题

数列与规律★★★☆☆
For every 3∘3^\circ rise in temperature, the volume of a certain gas expands by 4 cubic centimeters. If the volume of the gas is 24 cubic centimeters when the temperature is 32∘32^\circ , what was the volume of the gas in cubic centimeters when the temperature was 20∘20^\circ ?
温度每升高 3∘3^\circ,某气体的体积膨胀 4 立方厘米。如果温度为 32∘32^\circ 时气体体积为 24 立方厘米,则温度为 20∘20^\circ 时气体体积是多少立方厘米?
  1. A.8
  2. B.12
  3. C.15
  4. D.16
  5. E.40

正确答案 · Correct Answer

A

解析 · Solution

Solution 1

The temperature increased by 12∘12^{\circ}, so it increased by 3∘3^{\circ} four times. Since each 3∘3^{\circ} increase caused the volume of the gas to expand by 4 cubic centimeters, the gas expanded by a total of 4⋅4=164 \cdot 4 = 16 cubic centimeters. Therefore, the original volume of the gas was 24 - 16 = 8 cubic centimeters.

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