AMC 8 1993 Problem 19

AMC8 1993 年第 19 题

数列与规律★★★☆☆

题干整理中

  1. A.167,400
  2. B.172,050
  3. C.181,071
  4. D.199,300
  5. E.362,142

正确答案 · Correct Answer

A

解析 · Solution

Solution 1

We see that 1901=1800+101, 1902=1800+102, etc. Each term in the first set of numbers is 1800 more than the corresponding term in the second set; Because there are 93 terms in the first set, the expression can be paired up as follows and simplified:
(1901−101)+(1902−102)+(1903−103)+⋯+(1993−193)=1800+1800+⋯+1800=(1800)(93)=(A)167,400(1901-101) + (1902-102) + (1903-103) + \cdots + (1993-193)\\ =1800 + 1800 + \cdots + 1800\\ =(1800)(93)\\ =\text{(A)167,400}

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