AMC 8 1993 Problem 23

AMC8 1993 年第 23 题

逻辑推理(跨域)★★★☆☆
Five runners, PP , QQ , RR , SS , TT , have a race, and PP beats QQ , PP beats RR , QQ beats SS , and TT finishes after PP and before QQ . Who could NOT have finished third in the race?
五名跑步者 PP、QQ、RR、SS、TT 参加比赛。PP 击败 QQ,PP 击败 RR,QQ 击败 SS,TT 在 PP 之后、QQ 之前完赛。谁不可能获得第三名?
  1. A.P and QP\text{ and }Q
  2. B.P and RP\text{ and }R
  3. C.P and SP\text{ and }S
  4. D.P and TP\text{ and }T
  5. E.P,S and TP,S\text{ and }T

正确答案 · Correct Answer

C

解析 · Solution

Solution 1

First, note that PP must beat QQ, RR, TT, and by transitivity, SS. Thus PP is in first, and not in 3rd. Similarly, SS is beaten by PP, QQ, and by transitivity, TT, so SS is in fourth or fifth, and not in third. All of the others can be in third, as all of the following sequences show. Each follows all of the assumptions of the problem, and they are in order from first to last: PTQRS, PTRQS, PRTQS. Thus the answer is (C) P and S\text{(C)\ P\ \text{and}\ S}.

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