AMC 8 1994 Problem 25

AMC8 1994 年第 25 题

数列与规律★★★★☆
Find the sum of the digits in the answer to 9999⋯99⏟94 nines×4444⋯44⏟94 fours\underbrace{9999\cdots 99}_{94\text{ nines}} \times \underbrace{4444\cdots 44}_{94\text{ fours}} where a string of 94 nines is multiplied by a string of 94 fours.
求以下乘积的各位数字之和:
\underbrace{9999\cdots 99}_{94\text{ 个 9}} \times \underbrace{4444\cdots 44}_{94\text{ 个 4}}
即 94 个 9 组成的数乘以 94 个 4 组成的数。
  1. A.846
  2. B.855
  3. C.945
  4. D.954
  5. E.1072

正确答案 · Correct Answer

A

解析 · Solution

解法1

常规解法 · 找规律 观察 9⋅4=369\cdot4=36(数字和 9)、99⋅44=435699\cdot44=4356(数字和 18);一般地 nn 个 9 乘 nn 个 4 的数字和为 9n9n。故答案 9⋅94=8469\cdot94=846。

Solution 1

Elementary · find the pattern Notice the pattern: 9⋅4=369\cdot4=36 has digit sum 9, and 99⋅44=435699\cdot44=4356 has digit sum 18; in general a string of nn nines times nn fours has digit sum 9n9n. So the answer is 9⋅94=8469\cdot94=846.

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