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1994
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Problem 7
AMC 8 1994 Problem 7
AMC8 1994 年第 7 题
三角形
★★☆☆☆
If
∠
A
=
60
∘
\angle A = 60^\circ
∠
A
=
6
0
∘
,
∠
E
=
40
∘
\angle E = 40^\circ
∠
E
=
4
0
∘
and
∠
C
=
30
∘
\angle C = 30^\circ
∠
C
=
3
0
∘
, then
∠
B
D
C
=
\angle BDC =
∠
B
D
C
=
如果
∠
A
=
60
∘
\angle A = 60^\circ
∠
A
=
6
0
∘
，
∠
E
=
40
∘
\angle E = 40^\circ
∠
E
=
4
0
∘
，
∠
C
=
30
∘
\angle C = 30^\circ
∠
C
=
3
0
∘
，则
∠
B
D
C
=
\angle BDC =
∠
B
D
C
=
A.
40
∘
40^\circ
4
0
∘
B.
50
∘
50^\circ
5
0
∘
C.
60
∘
60^\circ
6
0
∘
D.
70
∘
70^\circ
7
0
∘
E.
80
∘
80^\circ
8
0
∘
正确答案 · Correct Answer
B
解析 · Solution
解析整理中
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