AMC 8 1996 Problem 19

AMC8 1996 年第 19 题

统计与数据图表★★★☆☆
The pie charts below indicate the percent of students who prefer golf, bowling, or tennis at East Junior High School and West Middle School. The total number of students at East is 2000 and at West, 2500. In the two schools combined, the percent of students who prefer tennis is
以下饼图显示了 East 初中和 West 中学喜欢高尔夫、保龄球或网球的学生百分比。East 共有 2000 名学生,West 共有 2500 名。两所学校合计,喜欢网球的学生的百分比是
AMC 8 1996 Problem 19 figure
  1. A.30%
  2. B.31%
  3. C.32%
  4. D.33%
  5. E.34%

正确答案 · Correct Answer

C

解析 · Solution

Solution 1

In the first school, 2000⋅22%=2000⋅0.22=4402000 \cdot 22\% = 2000 \cdot 0.22 = 440 students prefer tennis.
In the second school, 2500⋅40%=2500⋅0.40=10002500 \cdot 40\% = 2500 \cdot 0.40 = 1000 students prefer tennis.
In total, 440 + 1000 = 1440 students prefer tennis out of a total of 2000 + 2500 = 4500 students
This means 14404500⋅100%=32100⋅100%=32%\displaystyle \frac{1440}{4500} \cdot 100\% = \frac{32}{100} \cdot 100\% = 32\% of the students in both schools prefer tennis, giving answer (C) 32%\text{(C) 32\%}.

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