AMC 8 1996 Problem 2

AMC8 1996 年第 2 题

表达式与运算★☆☆☆☆

Jose, Thuy, and Kareem each start with the number 10 . Jose subtracts 1 from the number 10 , doubles his answer, and then adds 2 . Thuy doubles the number 10 , subtracts 1 from her answer, and then adds 2 . Kareem subtracts 1 from the number 10 , adds 2 to his number, and then doubles the result. Who gets the largest final answer?

Jose、Thuy 和 Kareem 各从数字 10 开始。Jose 从 10 中减去 1，将结果加倍，然后加上 2。Thuy 将 10 加倍，从中减去 1，然后加上 2。Kareem 从 10 中减去 1，加上 2，然后将结果加倍。谁得到最大的最终答案？

A. $\text{Jose}$
B. $\text{Thuy}$
C. $\text{Kareem}$
D. $\text{Jose and Thuy}$
E. $\text{Thuy and Kareem}$

正确答案 · Correct Answer

解析 · Solution

Solution 1

Jose gets 10 - 1 = 9, then

9 \cdot 2 = 18

, then 18 + 2 = 20.

Thuy gets

10 \cdot 2 = 20

, then 20 - 1 = 19, and then 19 + 2 = 21.

Kareem gets 10 - 1 = 9, then 9 + 2 = 11, and then

11\cdot 2 = 22

Thus, Kareem gets the highest number, and the answer is

C

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