AMC 8 1996 Problem 22

AMC8 1996 年第 22 题

三角形★★★☆☆
The horizontal and vertical distances between adjacent points equal 1 unit. What is the area of triangle ABCABC ?
相邻点之间的水平和垂直距离均为 1 个单位。三角形 ABCABC 的面积是多少?
AMC 8 1996 Problem 22 figure
  1. A.14\displaystyle \frac{1}{4}
  2. B.12\displaystyle \frac{1}{2}
  3. C.34\displaystyle \frac{3}{4}
  4. D.1
  5. E.54\displaystyle \frac{5}{4}

正确答案 · Correct Answer

B

解析 · Solution

Solution 1

△ADC\triangle ADC takes up half of the 4x3 grid, so it has area of 6.
△ABD\triangle ABD has height of BF = 2 and a base of AD = 4, for an area of 12⋅2⋅4=4\displaystyle \frac{1}{2} \cdot 2 \cdot 4 = 4.
△CBD\triangle CBD has height of BE = 1 and a base of CD = 3, for an area of 12⋅1⋅3=32\displaystyle \frac{1}{2} \cdot 1 \cdot 3 = \frac{3}{2}
Note that △ABC\triangle ABC can be found by taking △ADC\triangle ADC, and subtracting off △ABD\triangle ABD and △CBD\triangle CBD.
Thus, the area of △ABC=6−4−32=12\displaystyle \triangle ABC = 6 - 4 - \frac{3}{2} = \frac{1}{2}, and the answer is BB.
There are other equivalent ways of dissecting the figure; right triangles △ABF,△BCE\triangle ABF, \triangle BCE and rectangle □BEDF\square BEDF can also be used. You can also use △BEC\triangle{BEC} and trapezoid ADBEADBE.

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