AMC 8 1996 Problem 4

AMC8 1996 年第 4 题

数列与规律★★☆☆☆

题干整理中

  1. A.13\dfrac{1}{3}
  2. B.23\dfrac{2}{3}
  3. C.32\dfrac{3}{2}
  4. D.173\dfrac{17}{3}
  5. E.343\dfrac{34}{3}

正确答案 · Correct Answer

B

解析 · Solution

Solution 1

First, notice that each number in the numerator is a multiple of 2, and each number in the denominator is a multiple of 3. This suggests that each expression can be factored. Factoring gives:
2(1+2+3+⋯+17)3(1+2+3+⋯+17)\dfrac{2(1+2+3+\cdots + 17)}{3(1+2+3+\cdots + 17)}
Since all the material in the parentheses is the same, the common factor in the numerator and the denominator may be cancelled, leaving 23\displaystyle \frac{2}{3}, which is option BB.

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