AMC 8 1998 Problem 19

AMC8 1998 年第 19

概率★★★☆☆
Problem Tamika selects two different numbers at random from the set {8,9,10}\{ 8,9,10 \} and adds them. Carlos takes two different numbers at random from the set {3,5,6}\{3, 5, 6\} and multiplies them. What is the probability that Tamika's result is greater than Carlos' result?
从集合 {8,9,10}\{8,9,10\} 中随机选两个不同的数并相加。Carlos 从集合 {3,5,6}\{3,5,6\} 中随机选两个不同的数并相乘。Tamika 的结果大于 Carlos 的结果的概率是多少?
  1. A.49\dfrac{4}{9}
  2. B.59\dfrac{5}{9}
  3. C.12\dfrac{1}{2}
  4. D.13\dfrac{1}{3}
  5. E.23\dfrac{2}{3}

正确答案 · Correct Answer

A

解析 · Solution

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