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1998
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Problem 3
AMC 8 1998 Problem 3
AMC8 1998 年第 3 题
表达式与运算
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题干整理中
A.
1
B.
25
16
\dfrac{25}{16}
16
25
C.
2
D.
43
20
\dfrac{43}{20}
20
43
E.
47
16
\dfrac{47}{16}
16
47
正确答案 · Correct Answer
B
解析 · Solution
Solution 1
3
8
+
7
8
4
5
=
10
8
4
5
=
5
4
4
5
=
5
4
⋅
5
4
=
25
16
=
B
\displaystyle \frac{\frac{3}{8}+\frac{7}{8}}{\frac{4}{5}} = \frac{\frac{10}{8}}{\frac{4}{5}} = \frac{\frac{5}{4}}{\frac{4}{5}} = \frac{5}{4} \cdot \frac{5}{4} = \frac{25}{16} = B
5
4
8
3
+
8
7
=
5
4
8
10
=
5
4
4
5
=
4
5
⋅
4
5
=
16
25
=
B
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