AMC 8 1999 Problem 1

AMC8 1999 年第 1

表达式与运算☆☆☆☆
(6?3) + 4 - (2 - 1) = 5. To make this statement true, the question mark between the 6 and the 3 should be replaced by
要使等式 (6?3) + 4 - (2 - 1) = 5 成立,6 和 3 之间的问号应替换为
  1. A.÷\div
  2. B.×\times
  3. C.+
  4. D.-
  5. E.None of these / 以上都不对

正确答案 · Correct Answer

A

解析 · Solution

解析整理中

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