AMC 8 1999 Problem 21

AMC8 1999 年第 21 题

三角形★★★☆☆
The degree measure of angle AA is
角 AA 的度数是多少?
AMC 8 1999 Problem 21 figure
  1. A.20
  2. B.30
  3. C.35
  4. D.40
  5. E.45

正确答案 · Correct Answer

B

解析 · Solution

Solution 1

Angle-chasing using the small triangles:
Use the line below and to the left of the 110∘110^\circ angle to find that the rightmost angle in the small lower-left triangle is 180−110=70∘180 - 110 = 70^\circ.
Then use the small lower-left triangle to find that the remaining angle in that triangle is 180−70−40=70∘180 - 70 - 40 = 70^\circ.
Use congruent vertical angles to find that the lower angle in the smallest triangle containing AA is also 70∘70^\circ.
Next, use line segment ABAB to find that the other angle in the smallest triangle containing AA is 180−100=80∘180 - 100 = 80^\circ.
The small triangle containing AA has a 70∘70^\circ angle and an 80∘80^\circ angle. The remaining angle must be 180−70−80=30∘,B180 - 70 - 80 = 30^\circ, B
The third angle of the triangle containing the 100∘100^\circ angle and the 40∘40^\circ angle is 180∘−100∘−40∘=40∘180^\circ - 100^\circ - 40^\circ = 40^\circ. It follows that AA is the third angle of the triangle consisting of the found 40∘40^\circ angle and the given 110∘110^\circ angle. Thus, AA is a 180∘−110∘−40∘=30∘180^\circ - 110^\circ - 40^\circ = 30^\circ angle, and so the answer is 30∘,B30^\circ, \textbf{B}.

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