AMC 8 1999 Problem 3

AMC8 1999 年第 3 题

表达式与运算★☆☆☆☆
Which triplet of numbers has a sum NOT equal to 1?
下列哪组数字的和不等于 1?
  1. A.(12,13,16)\displaystyle \left(\frac{1}{2},\frac{1}{3},\frac{1}{6}\right)
  2. B.(2,-2,1)
  3. C.(0.1,0.3,0.6)
  4. D.(1.1,-2.1,1.0)
  5. E.(−32,−52,5)\displaystyle \left(-\frac{3}{2},-\frac{5}{2},5\right)

正确答案 · Correct Answer

D

解析 · Solution

Solution 1

By adding each triplet, we can see that gives us 0, not 1, as our sum.
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