AMC 8 2000 Problem 14

AMC8 2000 年第 14 题

余数与同余★★★☆☆
What is the units digit of 1919+999919^{19} + 99^{99} ?
1919+999919^{19} + 99^{99} 的个位数字是多少?
  1. A.0
  2. B.1
  3. C.2
  4. D.8
  5. E.9

正确答案 · Correct Answer

D

解析 · Solution

Solution 1

Finding a pattern for each half of the sum, even powers of 19 have a units digit of 1, and odd powers of 19 have a units digit of 9. So, 191919^{19} has a units digit of 9. Powers of 99 have the exact same property, so 999999^{99} also has a units digit of 9. 9+9=18 which has a units digit of 8, so the answer is DD.

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