AMC 8 2001 Problem 11

AMC8 2001 年第 11 题

坐标几何★★★☆☆
Points AA, BB, CC and DD have these coordinates: A(3,2)A(3,2), B(3,−2)B(3,-2), C(−3,−2)C(-3,-2) and D(−3,0)D(-3, 0). The area of quadrilateral ABCDABCD is
点 AA,BB,CC 和 DD 有如下坐标:A(3,2)A(3,2),B(3,−2)B(3,-2),C(−3,−2)C(-3,-2),D(−3,0)D(-3,0),则四边形 ABCDABCD 的面积为
  1. A.12
  2. B.15
  3. C.18
  4. D.21
  5. E.24

正确答案 · Correct Answer

C

解析 · Solution

Solution 1

Using the diagram above, the figure can be divided along the x-axis into two familiar regions that do not overlap: a right triangle and a rectangle. Since the areas do not overlap, the area of the entire trapezoid is the sum of the area of the triangle and the area of the rectangle. Atrap=Atri+ArectA_{trap} = A_{tri} + A_{rect}, Atrap=12bh+lw\displaystyle A_{trap} = \frac{1}{2} bh + lw, Atrap=12⋅6⋅2+6⋅2\displaystyle A_{trap} = \frac{1}{2} \cdot 6 \cdot 2 + 6\cdot 2, Atrap=6+12=18→CA_{trap} = 6 + 12 = 18 \rightarrow C

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