AMC 8 2002 Problem 18

AMC8 2002 年第 18 题

方程与不等式★★★☆☆
Gage skated 1 hr 15 min each day for 5 days and 1 hr 30 min each day for 3 days. How long would he have to skate the ninth day in order to average 85 minutes of skating each day for the entire time?
Gage 连续 5 天每天滑冰 1 小时 15 分钟,连续 3 天每天滑冰 1 小时 30 分钟。那么第九天他需要滑多长时间才能使得在全部时间内每天平均滑 85 分钟?
  1. A.1 hr\text{1 hr}
  2. B.1 hr 10 min\text{1 hr 10 min} / 1 小时 10 分钟
  3. C.1 hr 20 min\text{1 hr 20 min} / 1 小时 20 分钟
  4. D.1 hr 40 min\text{1 hr 40 min} / 1 小时 40 分钟
  5. E.2 hr\text{2 hr}

正确答案 · Correct Answer

E

解析 · Solution

Solution 1

Converting into minutes and adding, we get that she skated 75*5+90*3+x = 375+270+x = 645+x minutes total, where xx is the amount she skated on day 9. Dividing by 9 to get the average, we get 645+x9=85\displaystyle \frac{645+x}{9} = 85. Solving for xx, 645+x=765 x=120 Now we convert back into hours and minutes to get (E)2 hr\text{(E)2\ \text{hr}}.

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