AMC 8 2003 Problem 19

AMC8 2003 年第 19 题

整除与因数★★★☆☆
How many integers between 1000 and 2000 have all three of the numbers 15, 20, and 25 as factors?
1000 和 2000 之间有多少个整数,满足 15,20 和 25 都是它的因子?
  1. A.1
  2. B.2
  3. C.3
  4. D.4
  5. E.5

正确答案 · Correct Answer

C

解析 · Solution

Solution 1

Find the least common multiple of 15, 20, 25 by turning the numbers into their prime factorization. 15=3⋅5,20=22⋅5,25=5215 = 3 \cdot 5, 20 = 2^2 \cdot 5, 25 = 5^2 Gather all necessary multiples 3,22,523, 2^2, 5^2 when multiplied gets 300. The multiples of 300 - 300, 600, 900, 1200, 1500, 1800, 2100. The number of multiples between 1000 and 2000 is 3.

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