AMC 8 2004 Problem 9

AMC8 2004 年第 9 题

统计与数据图表★★☆☆☆
The average of the five numbers in a list is 54 . The average of the first two numbers is 48 . What is the average of the last three numbers?
一列 5 个数的平均值为 54。已知前 2 个数的平均值为 48。则最后 3 个数的平均值是多少?
  1. A.55
  2. B.56
  3. C.57
  4. D.58
  5. E.59

正确答案 · Correct Answer

D

解析 · Solution

Solution 1

Let the 5 numbers be a, b, c, d, and ee. Thus a+b+c+d+e5=54\displaystyle \frac{a+b+c+d+e}{5} = 54 and a+b+c+d+e = 270. Since a+b2=48\displaystyle \frac{a+b}{2} = 48, a+b = 96. Substituting back into our original equation, we have 96+c+d+e = 270 and c+d+e = 174. Dividing by 3 gives the average of 58.

继续练习

真题版权归属 MAA(AMC)。本站仅供学习用途。版权方如有异议,请联系本站予以下架。

Problems © MAA (AMC). This site is for study purposes only. Rightsholders may contact us for removal.