AMC 8 2006 Problem 11

AMC8 2006 年第 11 题

整除与因数★★★☆☆
How many two-digit numbers have digits whose sum is a perfect square?
有多少个两位数,满足各个位上数字之和是个完全平方数?
  1. A.13
  2. B.16
  3. C.17
  4. D.18
  5. E.19

正确答案 · Correct Answer

C

解析 · Solution

Solution 1

There is 1 integer whose digits sum to 1: 10. There are 4 integers whose digits sum to 4: 13,22,31,and 4013, 22, 31, \text{and } 40. There are 9 integers whose digits sum to 9: 18,27,36,45,54,63,72,81,and 9018, 27, 36, 45, 54, 63, 72, 81, \text{and } 90. There are 3 integers whose digits sum to 16: 79,88,and 9779, 88, \text{and } 97. Two digits cannot sum to 25 or any greater square since the greatest sum of digits of a two-digit number is 9 + 9 = 18. Thus, the answer is 1 + 4 + 9 + 3 = 17.

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