AMC 8 2009 Problem 13

AMC8 2009 年第 13

概率★★★☆☆
A three-digit integer contains one of each of the digits 1, 3, and 5. What is the probability that the integer is divisible by 5?
一个三位整数包含了数字 1,3 和 5,且每个出现一次。那么这个整数能被 5 整除的概率是多少?
  1. A.16\displaystyle \frac{1}{6}
  2. B.13\displaystyle \frac{1}{3}
  3. C.12\displaystyle \frac{1}{2}
  4. D.23\displaystyle \frac{2}{3}
  5. E.56\displaystyle \frac{5}{6}

正确答案 · Correct Answer

B

解析 · Solution

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