AMC 8 2010 Problem 11

AMC8 2010 年第 11 题

比与比例★★★☆☆
The top of one tree is 16 feet higher than the top of another tree. The heights of the two trees are in the ratio 3:43:4 . In feet, how tall is the taller tree?
一棵树的顶部比另一棵树的顶部高 16 英尺。这两棵树的高度之比是 3:4。那么较高的那棵树高多少英尺?
  1. A.48
  2. B.64
  3. C.80
  4. D.96
  5. E.112

正确答案 · Correct Answer

B

解析 · Solution

Solution 1

To answer this problem, you have to make it so that we have the same proportion as 3:4, but the difference between them is 16. Since the two numbers in the ratio are consecutive (difference of 1), if we multiply both of them by 16, we would get a difference of 16 between them. So, it would be 48:64 and since we need to find the height of the taller tree, we get h=64⇒64h=64 \Rightarrow 64. s + 16 = t, 3t = 4s. Solving by substitution, 34t+16=t\displaystyle \frac{3}{4} t + 16 = t, 16=14t\displaystyle 16 = \frac{1}{4} t, t=64. Assume the ratio is represented through xx. Then, 4x=3x+16, meaning x=16. Plug back into 4x4x to get t=64 -N. Video by MathTalks https:

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