AMC 8 2010 Problem 19

AMC8 2010 年第 19 题

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The two circles pictured have the same center C . Chord AD‾\overline{AD} is tangent to the inner circle at B , AC is 10 , and chord AD‾\overline{AD} has length 16 . What is the area between the two circles?
下图中的两个圆是同心圆,圆心都是 CC。弦 AD‾\overline{AD} 与内圆切于 BB,ACAC 长为 10,弦 AD‾\overline{AD} 长为 16。那么这两个圆之间区域的面积是多少?
AMC 8 2010 Problem 19 figure
  1. A.36π36 \pi
  2. B.49π49 \pi
  3. C.64π64 \pi
  4. D.81π81 \pi
  5. E.100π100 \pi

正确答案 · Correct Answer

C

解析 · Solution

Solution 1

Since △ACD\triangle ACD is isosceles, CBCB bisects ADAD. Thus AB=BD=8. From the Pythagorean Theorem, CB=6. Thus the area between the two circles is 100π−36π=64π100\pi - 36\pi=64\pi

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