AMC 8 2010 Problem 2

AMC8 2010 年第 2 题

表达式与运算★☆☆☆☆
If a @ b = a×ba+b\displaystyle \frac{a\times b}{a+b} for a,b positive integers, then what is 5 @ 10 ?
对于正整数 aa、bb,定义 a@b=a×ba+b\displaystyle a @ b = \frac{a\times b}{a+b}。那么 $5 @ 10$ 等于多少?
  1. A.310\displaystyle \frac{3}{10}
  2. B.1
  3. C.2
  4. D.103\displaystyle \frac{10}{3}
  5. E.50

正确答案 · Correct Answer

D

解析 · Solution

Solution 1

Substitute a=5 and b=10 into the expression for $a @ b$ to get: 5@10=5×105+10=5015=103\displaystyle 5 @ 10 = \frac{5×10}{5+10} = \frac{50}{15} = \frac{10}{3} Thus, answer choice 103\displaystyle \frac{10}{3} is correct. Video by MathTalks https:

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