AMC 8 2013 Problem 24

AMC8 2013 年第 24 题

面积与周长(综合)★★★★☆
Squares ABCD , EFGH , and GHIJ are equal in area. Points C and D are the midpoints of sides IH and HE , respectively. What is the ratio of the area of the shaded pentagon AJICB to the sum of the areas of the three squares?
正方形 ABCD,EFGH 和 GHIJ 的面积都相等。点 C 和点 D 分别是边 IH 和 HE 的中点。那么阴影部分五边形 AJICB 的面积和三个正方形面积总和的比值是多少?
AMC 8 2013 Problem 24 figure
  1. A.14\displaystyle \hspace{.05in}\frac{1}{4}
  2. B.724\displaystyle \hspace{.05in}\frac{7}{24}
  3. C.13\displaystyle \hspace{.05in}\frac{1}{3}
  4. D.38\displaystyle \hspace{.05in}\frac{3}{8}
  5. E.512\displaystyle \hspace{.05in}\frac{5}{12}

正确答案 · Correct Answer

C

解析 · Solution

解法1

常规解法 · 坐标算面积 设每个正方形边长 1(三方共 3)。按图取 A(0.5,2)A(0.5,2)、B(1.5,2)B(1.5,2)、C(1.5,1)C(1.5,1)、I(2,1)I(2,1)、J(2,0)J(2,0)。设直线 EIEI 与 AJAJ 交于 XX,把阴影五边形拆为梯形 ABCXABCX 与三角形 XIJXIJ;因 XX 是 AJAJ 中点得 XC=0.25,面积分别为 0.625、0.375,合计 1。比值 13\dfrac13。

Solution 1

Elementary · area by coordinates Take each square to have side 1 (three squares total 3). Place A(0.5,2)A(0.5,2), B(1.5,2)B(1.5,2), C(1.5,1)C(1.5,1), I(2,1)I(2,1), J(2,0)J(2,0). Let XX be where EIEI meets AJAJ and split the shaded pentagon into trapezoid ABCXABCX and triangle XIJXIJ; since XX is the midpoint of AJAJ, XC=0.25, giving areas 0.625 and 0.375 that sum to 1. The ratio is 13\dfrac13.

继续练习

真题版权归属 MAA(AMC)。本站仅供学习用途。版权方如有异议,请联系本站予以下架。

Problems © MAA (AMC). This site is for study purposes only. Rightsholders may contact us for removal.