AMC 8 2014 Problem 25

AMC8 2014 年第 25 题

圆★★★★☆
A straight one-mile stretch of highway, 40 feet wide, is closed. Robert rides his bike on a path composed of semicircles as shown. If he rides at 5 miles per hour, how many hours will it take to cover the one-mile stretch? Note: 1 mile = 5280 feet
一段长为 1 英里,宽 40 英尺的高速公路被关闭了。Robert 沿着如下图中由一系列半圆组成的路径骑着自行车。若他骑车的速度是 5 英里每小时,那么走过这段 1 英里的高速公路需要多少小时? 注意:1 英里=5280 英尺
AMC 8 2014 Problem 25 figure
  1. A.π11\displaystyle \frac{\pi}{11}
  2. B.π10\displaystyle \frac{\pi}{10}
  3. C.π5\displaystyle \frac{\pi}{5}
  4. D.2π5\displaystyle \frac{2\pi}{5}
  5. E.2π3\displaystyle \frac{2\pi}{3}

正确答案 · Correct Answer

B

解析 · Solution

解法1

常规解法 · 数半圆 每个半圆直径等于路宽 40 英尺,半径 20。一英里 =5280 英尺,含 5280/40=132 个半圆。每个弧长 π⋅20=20π\pi\cdot20=20\pi 英尺,总长 132×20π=2640π132×20\pi=2640\pi 英尺 =2640π5280=π2=\dfrac{2640\pi}{5280}=\dfrac{\pi}{2} 英里。时间 π/25=π10\dfrac{\pi/2}{5}=\dfrac{\pi}{10} 小时。

Solution 1

Elementary · count the semicircles Each semicircle has diameter 40 ft (the road width), radius 20. A mile is 5280 ft, giving 5280/40=132 semicircles. Each arc is π⋅20=20π\pi\cdot20=20\pi ft, so the total is 132⋅20π=2640π132\cdot20\pi=2640\pi ft =2640π5280=π2=\dfrac{2640\pi}{5280}=\dfrac{\pi}{2} miles. The time is π/25=π10\dfrac{\pi/2}{5}=\dfrac{\pi}{10} hours.

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