AMC 8 2015 Problem 10

AMC8 2015 年第 10 题

基本计数原理★★☆☆☆
How many integers between 1000 and 9999 have four distinct digits?
1000 和 9999 之间有多少个四位数,满足这个数的四个位上数字都不相同?
  1. A.3024
  2. B.4536
  3. C.5040
  4. D.6480
  5. E.6561

正确答案 · Correct Answer

B

解析 · Solution

Solution 1

There are 9 choices for the first number, since it cannot be 0, there are only 9 choices left for the second number since it must differ from the first, 8 choices for the third number, since it must differ from the first two, and 7 choices for the fourth number, since it must differ from all three. This means there are 9×9×8×7=45369×9 \times 8×7=4536 integers between 1000 and 9999 with four distinct digits. If you're too lazy to do 9×9×8×7=45369×9 \times 8×7= 4536, we can notice 9×9 = 81 and 8×7=56 The unit digit must be 6. Therefore, the answer is the only answer choice with a unit digit of 6, which is BB.

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