AMC 8 2016 Problem 21

AMC8 2016 年第 21 题

概率★★★☆☆
A top hat contains 3 red chips and 2 green chips. Chips are drawn randomly, one at a time without replacement, until all 3 of the reds are drawn or until both green chips are drawn. What is the probability that the 3 reds are drawn?
一个罐子里装有 3 个红色筹码和 2 个绿色筹码。现在将筹码一个个随机抽出且不放回,直到 3 个红色筹码被全部取出或者 2 个绿色筹码被全部取出,这时取出动作立即停止,那么取出 3 个红色筹码的概率是多少?
  1. A.310\dfrac{3}{10}
  2. B.25\dfrac{2}{5}
  3. C.12\dfrac{1}{2}
  4. D.35\dfrac{3}{5}
  5. E.710\dfrac{7}{10}

正确答案 · Correct Answer

B

解析 · Solution

Solution 1

We put five chips randomly in order and then pick the chips from the left to the right. To find the number of ways to rearrange the three red chips and two green chips, we solve for (52)=10\binom{5}{2} = 10. However, we notice that whenever the last chip we draw is red, we pick both green chips before we pick the last red chip. Similarly, when the last chip is green, we pick all three red chips before the last green chip. This means that the last chip must be green in all the situations that work. This means we are left with finding the number of ways to rearrange three red chips and one green chip, which is (43)=4\binom{4}{3} = 4. Because a green chip will be last 4 out of the 10 situations, our answer is 25\displaystyle \frac{2}{5}.

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