AMC 8 2017 Problem 12

AMC8 2017 年第 12 题

整除与因数★★★☆☆

The smallest positive integer greater than 1 that leaves a remainder of 1 when divided by 4, 5, and 6 lies between which of the following pairs of numbers?

大于 1 且除以 4,5 和 6 所得余数均为 1 的最小正整数在下面哪两个数之间？

A. $2\text{ and }19$
B. $20\text{ and }39$
C. $40\text{ and }59$
D. $60\text{ and }79$
E. $80\text{ and }124$

正确答案 · Correct Answer

D

解析 · Solution

解析整理中

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