AMC 8 2018 Problem 3

AMC8 2018 年第 3 题

基本计数原理★★☆☆☆
Students Arn, Bob, Cyd, Dan, Eve, and Fon are arranged in that order in a circle. They start counting: Arn first, then Bob, and so forth. When the number contains a 7 as a digit (such as 47) or is a multiple of 7 that person leaves the circle and the counting continues. Who is the last one present in the circle?
Arn,Bob,Cyd,Dan,Eve 和 Fon 以这样的顺序围成一圈。他们开始数数:Arn 先开始,然后 Bob,以此类推。当数包含数字 7(例如 47)或者是 7 的倍数时,那个人就离开圆圈,数数继续进行。最后一个离开圆圈的是谁?
  1. A.Arn\text{Arn}
  2. B.Bob\text{Bob}
  3. C.Cyd\text{Cyd}
  4. D.Dan\text{Dan}
  5. E.Eve\text{Eve}

正确答案 · Correct Answer

D

解析 · Solution

Solution 1

Assign each person a position: Arn is in position 1, Bob in 2, etc. Note that if there are nn people standing in a circle, a person will say a number that is congruent to their position modulo nn. It follows that if there are kk numbers to be said (with someone leaving on the $kth$ ), the person that leaves will stand in position k(modn).k\pmod{n}. The five numbers which cause people to leave the circle are 7, 14, 17, 21, and 27. Since there are initially 6 people in the circle, so the person who leaves stands in position 7≡1(mod6)7\equiv 1\pmod 6, or position 1. Arn now leaves, and because Bob is the next person to say a number, we reassign the positions such that Bob is in position 1, Cyd in 2, and Fon in 5. There are 7 more numbers to be said, and someone leaves on the 7th. It follows that the person who leaves stands in position 7≡2(mod5)7\equiv 2\pmod 5. Cyd leaves the circle, and 4 people remain, namely Bob, Dan, Eve, and Fon. Assign the position numbers such that Dan has 1, Eve 2, etc. There are 3 more numbers to be said, and someone leaves on the 3rd. The person standing in position 3 (Fon) now leaves. There are two people left, Eve and Dan, with Dan in position 1 now. There are 6 more numbers to be said, and Eve is standing in position 6≡0(mod2)6\equiv 0\pmod 2, so she leaves. The last person standing is textDantext{Dan}. -Benedict T (countmath1)

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