AMC 8 2019 Problem 19
AMC8 2019 年第 19 题
基本计数原理★★★☆☆
In a tournament there are six teams that play each other twice. A team earns 3 points for a win, 1 point for a draw, and 0 points for a loss. After all the games have been played it turns out that the top three teams earned the same number of total points. What is the greatest possible number of total points for each of the top three teams?
在一场循环赛中，一共有 6 支队伍，每两支队伍之间都要比赛 2 次。某个队伍赢一次得 3 分，平局得 1 分，输了则得 0 分。当所有比赛都结束后，结果发现排名前三的队伍得分相同。问排名前三的队伍每支队最多可能得多少分？
- A.22
- B.23
- C.24
- D.26
- E.30
正确答案 · Correct Answer
C
解析 · Solution
解析整理中
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