AMC 8 2020 Problem 12

AMC8 2020 年第 12 题

整除与因数★★★☆☆
For a positive integer nn , the factorial notation n! represents the product of the integers from nn to 1 . What value of NN satisfies the following equation?
5!⋅9!=12⋅N!5!\cdot 9!=12\cdot N!
对一个正整数 n,符号 n!表示从 n 到 1 的所有整数的乘积。例如, 6!=6·5·4·3·2·3.2·1 则 N 为何值时,满足下面的方程?
  1. A.10
  2. B.11
  3. C.12
  4. D.13
  5. E.14

正确答案 · Correct Answer

A

解析 · Solution

Solution 1

We have 5!=2⋅3⋅4⋅55! = 2 \cdot 3 \cdot 4 \cdot 5, and 2⋅5⋅9!=10⋅9!=10!2 \cdot 5 \cdot 9! = 10 \cdot 9! = 10!. Therefore, the equation becomes 3⋅4⋅10!=12⋅N!3 \cdot 4 \cdot 10! = 12 \cdot N!, and so 12⋅10!=12⋅N!12 \cdot 10! = 12 \cdot N!. Cancelling the 12 s, it is clear that N=10. Since 5! = 120, we obtain 120⋅9!=12⋅N!120\cdot 9!=12\cdot N!, which becomes 12⋅10⋅9!=12⋅N!12\cdot 10\cdot 9!=12\cdot N! and thus 12⋅10!=12⋅N!12 \cdot 10!=12\cdot N!. We therefore deduce N=10. We can see that the answers (B)\textbf{(B)} to (E)\textbf{(E)} contain a factor of 11, but there is no such factor of 11 in 5!⋅9!5! \cdot 9!. The factor 11 is in every answer choice except 10, so four of the possible answers are eliminated. Therefore, the answer must be 10. by HW73

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