AMC 8 2023 Problem 16

AMC8 2023 年第 16 题

数列与规律★★★☆☆
The letters P\text{P}, Q\text{Q}, and R\text{R} are entered into a 20×2020\times 20 table according to the pattern shown below. How many P\text{P}'s, Q\text{Q}'s, and R\text{R}'s will appear in the completed table?
将字母 P\text{P}、Q\text{Q}、R\text{R} 按下图所示的规律填入 20×2020\times 20 的方格表中。问在完成的表中,各会出现多少个 P\text{P}、多少个Q\text{Q}、多少个R\text{R}?
AMC 8 2023 Problem 16 figure
  1. A. 132 Ps, 134 Qs, 134 Rs~132\text{ Ps, }134\text{ Qs, }134\text{ Rs}
  2. B. 133 Ps, 133 Qs, 134 Rs~133\text{ Ps, }133\text{ Qs, }134\text{ Rs}
  3. C. 133 Ps, 134 Qs, 133 Rs~133\text{ Ps, }134\text{ Qs, }133\text{ Rs}
  4. D. 134 Ps, 132 Qs, 134 Rs~134\text{ Ps, }132\text{ Qs, }134\text{ Rs}
  5. E. 134 Ps, 133 Qs, 133 Rs~134\text{ Ps, }133\text{ Qs, }133\text{ Rs}

正确答案 · Correct Answer

C

解析 · Solution

Solution 1

Since 20≡2(mod3)20\equiv2\pmod3 and Q\text{Q} is in the 2nd diagonal, it is also in the 20th diagonal, and so we find that there are 2(2+5+8+11+14+17)+20=134Qs2(2 + 5 + 8 + 11 + 14 + 17) + 20 = 134 \text{Qs}. Since all the P\text{P} 's and R\text{R} 's are symmetric, the answer is textPs,134 Qs, 133 Rs.text{ Ps,134\text{ Qs, }133\text{ Rs}}. user I lik math

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