AMC 8 2026 Problem 11

AMC8 2026 年第 11 题

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Squares of side length 1, 1, 2, 3, and 5 are arranged to form the rectangle shown below. A curve is drawn by inscribing a quarter circle in each square and joining the quarter circles in order, from shortest to longest. What is the length of the curve?
边长分别为 1、1、2、3 和 5 的正方形被排列成如下所示的矩形。在每个正方形内画一个四分之一圆,并按从小到大的顺序将这些四分之一圆连接起来形成一条曲线。这条曲线的长度是多少?
AMC 8 2026 Problem 11 figure
  1. A.4π4\pi
  2. B.6π6\pi
  3. C.(132)π\displaystyle (\frac{13}{2})\pi
  4. D.8π8\pi
  5. E.13π13\pi

正确答案 · Correct Answer

B

解析 · Solution

解法1

各段均为四分之一圆弧,弧长 =π2r\displaystyle = \frac{\pi}{2}r。提取公因子 π2\displaystyle \frac{\pi}{2}:总长 =π2×(1+1+2+3+5)=π2×12=6π\displaystyle = \frac{\pi}{2} \times (1+1+2+3+5) = \frac{\pi}{2} \times 12 = 6\pi。

Solution 1

Each arc is a quarter-circle with arc length π2r\displaystyle \frac{\pi}{2}r. Extracting the common factor π2\displaystyle \frac{\pi}{2}: total =π2×(1+1+2+3+5)=π2×12=6π\displaystyle = \frac{\pi}{2} \times (1 + 1 + 2 + 3 + 5) = \frac{\pi}{2} \times 12 = 6\pi.

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