考点组合概率统计

统计与数据图表

考什么 · What it tests

考四个统计量(平均数、中位数、众数、极差)怎么算、怎么读图表,以及反过来——已知平均数去倒推缺失的那个数据。
Tests the four summary stats (mean, median, mode, range) — how to compute them, how to read them off charts, and the reverse: given the average, recover a missing data point.

需要先会 · Prerequisites

  • 平均数 = 总和 ÷ 个数 / Mean = total ÷ count
  • 分数与百分比 / Fractions and percentages
  • 排序(找中位数前要先排队) / Sorting (order the data before finding the median)

常见套路 · Common moves

  1. 反推先还原总和:已知 nn 个数平均是 mm,就先算出总和 n×mn\times m,缺的那个数 = 总和减去其余——「均值反推」题几乎都靠这一步。
    To work backwards, first rebuild the total: if nn numbers average mm, the total is n×mn\times m, and the missing number equals the total minus the rest — nearly every reverse-mean problem hinges on this.
  2. 中位数先排序再数位置:奇数个取正中间,偶数个取中间两个的平均;没排序就报数一定错。
    For the median, sort first then locate: the middle one if the count is odd, the average of the middle two if even; report without sorting and you will be wrong.
  3. 加权平均别直接平均:各组人数不同时要按人数加权,用 \frac{\text{各组总和}}{\text{总人数}},不是几个平均数再取平均。
    Weighted average is not a plain average: when groups differ in size, weight by size using sum of all groupstotal count\displaystyle \frac{\text{sum of all groups}}{\text{total count}}, not the average of the group averages.

易错点 · Common pitfalls

  • 中位数忘了排序,直接取原始数据里居中那个——出题人专门把数据打乱顺序给你。
    Forgetting to sort and taking the physically middle value of the raw list — the writers hand you the data out of order on purpose.
  • 把「加权平均」当成「几个平均数的平均」:两个班的平均分不能直接相加除以 2,人数不同结果就不同。
    Treating a weighted average as the average of averages: two classes' mean scores can't just be added and halved — different class sizes change the result.
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