AMC 8 1985 Problem 1

AMC8 1985 年第 1 题

表达式与运算★☆☆☆☆

题干整理中

  1. A.1
  2. B.0
  3. C.49
  4. D.149\displaystyle \frac{1}{49}
  5. E.50

正确答案 · Correct Answer

A

解析 · Solution

Solution 1

By the commutative property: 3×59×11×7×9×113×5×7=3×5×7×9×119×11×3×5×7=3×5×7×9×113×5×7×9×11=1\displaystyle \frac{3×5}{9×11}\times \frac{7×9\times 11}{3×5\times 7}=\frac{3×5\times 7×9 \times 11}{9×11×3 \times 5×7}= \frac{3×5 \times 7×9 \times 11}{3×5 \times 7×9 \times 11}= 1

继续练习

真题版权归属 MAA(AMC)。本站仅供学习用途。版权方如有异议,请联系本站予以下架。

Problems © MAA (AMC). This site is for study purposes only. Rightsholders may contact us for removal.