AMC 8 1985 Problem 2

AMC8 1985 年第 2 题

数列与规律★☆☆☆☆

题干整理中

  1. A.845
  2. B.945
  3. C.1005
  4. D.1025
  5. E.1045

正确答案 · Correct Answer

B

解析 · Solution

Solution 1

Rearrange the terms to form 5 pairs, each of which sums to 189: $$$$90+91+⋯+98+99=(90+99)+(91+98)+(92+97)+(93+96)+(94+95)=189+189+189+189+189=189⋅5=945\begin{aligned} 90+91+\cdots +98+99 &= (90+99)+(91+98)+(92+97)+(93+96)+(94+95) \\ &= 189+189+189+189+189 \\ &= 189 \cdot 5 \\ &=945 \end{aligned}$$$$

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