AMC 8 1985 Problem 10

AMC8 1985 年第 10 题

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The fraction halfway between 15\displaystyle \frac{1}{5} and 13\displaystyle \frac{1}{3} (on the number line) is
数轴上 15\displaystyle \frac{1}{5} 和 13\displaystyle \frac{1}{3} 正中间的分数是
AMC 8 1985 Problem 10 figure
  1. A.14\displaystyle \frac{1}{4}
  2. B.215\displaystyle \frac{2}{15}
  3. C.415\displaystyle \frac{4}{15}
  4. D.53200\displaystyle \frac{53}{200}
  5. E.815\displaystyle \frac{8}{15}

正确答案 · Correct Answer

C

解析 · Solution

Solution 1

The fraction halfway between 15\displaystyle \frac{1}{5} and 13\displaystyle \frac{1}{3} is their average, which is 12(15+13)=12(815)=415\displaystyle \frac{1}{2}\left(\frac{1}{5}+\frac{1}{3}\right) = \frac{1}{2}\left(\frac{8}{15}\right) = \frac{4}{15}

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