AMC 8 1985 Problem 9

AMC8 1985 年第 9 题

表达式与运算★★☆☆☆
The product of the 9 factors
9 个因子之积
  1. A.110\displaystyle \frac {1}{10}
  2. B.19\displaystyle \frac {1}{9}
  3. C.12\displaystyle \frac {1}{2}
  4. D.1011\displaystyle \frac {10}{11}
  5. E.112\displaystyle \frac {11}{2}

正确答案 · Correct Answer

A

解析 · Solution

Solution 1

Simplifying each factor and cancelling yields (1−12)(1−13)(1−14)⋯(1−110)=(12)(23)(34)⋯(910)=1⋅2⋅3⋅4⋅5⋅6⋅7⋅8⋅92⋅3⋅4⋅5⋅6⋅7⋅8⋅9⋅10=110\displaystyle \Big(1 - \frac12\Big)\Big(1 - \frac13\Big)\Big(1 - \frac14\Big)\cdots\Big(1 - \frac {1}{10}\Big) =\left(\frac{1}{2}\right)\left(\frac{2}{3}\right)\left(\frac{3}{4}\right)\cdots\left(\frac{9}{10}\right) = \frac{1\cdot2\cdot3\cdot4\cdot5\cdot6\cdot7\cdot8\cdot9}{2\cdot3\cdot4\cdot5\cdot6\cdot7\cdot8\cdot9\cdot10} = \frac{1}{10}.

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