AMC 8 1985 Problem 8

AMC8 1985 年第 8

表达式与运算★★☆☆☆
If a = - 2, the largest number in the set {3a,4a,24/a,a2,1}\{ - 3a, 4a, 24/a, a^2, 1\} is
a = -2,集合 {3a,4a,24/a,a2,1}\{-3a, 4a, 24/a, a^2, 1\} 中最大的数是
  1. A.-3a
  2. B.4a
  3. C.24a\displaystyle \frac {24}{a}
  4. D.a^2
  5. E.1

正确答案 · Correct Answer

A

解析 · Solution

解析整理中

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