AMC 8 1991 Problem 11

AMC8 1991 年第 11 题

排列与组合★★★☆☆
There are several sets of three different numbers whose sum is 15 which can be chosen from {1,2,3,4,5,6,7,8,9}\{ 1,2,3,4,5,6,7,8,9 \} . How many of these sets contain a 5 ?
从 {1,2,3,4,5,6,7,8,9}\{1,2,3,4,5,6,7,8,9\} 中可以选出几组三个不同数的集合,其和为 15?这些集合中有多少个包含 5?
  1. A.3
  2. B.4
  3. C.5
  4. D.6
  5. E.7

正确答案 · Correct Answer

B

解析 · Solution

Solution 1

Let the three-element set be {a,b,c}\{ a,b,c \} and suppose that a=5.
We need b+c=10 and b≠cb\neq c. This gives us four solutions, so there are 4 sets with a 5 also with the desired properties →B\rightarrow \text{B}.

继续练习

真题版权归属 MAA(AMC)。本站仅供学习用途。版权方如有异议,请联系本站予以下架。

Problems © MAA (AMC). This site is for study purposes only. Rightsholders may contact us for removal.