AMC 8 1991 Problem 12

AMC8 1991 年第 12 题

比与比例★★★☆☆
If 2+3+43=1990+1991+1992N\displaystyle \frac{2+3+4}{3}=\frac{1990+1991+1992}{N} , then N=
若 2+3+43=1990+1991+1992N\displaystyle \frac{2+3+4}{3}=\frac{1990+1991+1992}{N},则 N=
  1. A.3
  2. B.6
  3. C.1990
  4. D.1991
  5. E.1992

正确答案 · Correct Answer

D

解析 · Solution

Solution 1

Note that for all integers n≠0n\neq 0, (n−1)+n+(n+1)n=3.\displaystyle \frac{(n-1)+n+(n+1)}{n} =3. Thus, we must have N=1991→DN=1991 \rightarrow \text{D}.

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